Rather that trying to shoehorn pack into a solution, it seems simpler to me to regex it (caution: needs Perl version 5.10+ for  \K operator): 

c:\@Work\Perl\monks\kanikas16>perl -wMstrict -le
"use 5.010;
 ;;
 my $s = '(1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 '
       .  '2 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 1 '
       .  '3 1 1 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 '
       . '10 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 1 '
       . '11 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 '
       . '987 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0)'
       ;
 print qq{<<$s>> \n};
 ;;
 my $bar = qq{\n} . 'x' x 35 . qq{\n};
 $s =~ s{ \A \( \K }{\n}xms;
 $s =~ s{ \d+ \s+ (?: [01] \s+){17} \K }{$bar}xmsg;
 print qq{<<$s>>};
"
<<(1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 2 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0
+ 0 1 3 1 1
 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 10 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 1 11
+ 1 1 0 0 0
 1 0 0 0 1 0 0 0 0 0 0 0 987 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0)>>

<<(
1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
2 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 1
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
3 1 1 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
10 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 1
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
11 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
987 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0)>>

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This is based on the updated version of kanikas16's OP and (almost!) exactly produces the desired output. The only thing I can't get simply via substitutions is the use of a 36-'x' separator after row 8 (per the OP) rather than the 35-'x' separator used everywhere else. I'm assuming (and hoping!) this is just a typo; it would be possible to accommodate something like this with a substitution, but messy! (Note: This solution needs Perl 5.10+ for the  \K operator, but a non-\K solution is fairly painless; let me know if it's needed.)

Give a man a fish:  <%-{-{-{-<

In reply to Re: Count and print in perl by AnomalousMonk
in thread Count and print in perl by kanikas16

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