I need to get the first two fields of a log file containing a certain string starting from the end of the file.
Using this I get the whole last line line containing the string:
$ perl -ne '$l=$_ if /received/; END{print $l}' /var/log/rsync.log
2017/04/20 10:50:24 [26050] sent 25 bytes received 326 bytes total s
+ize 52165551
How could I get the date fields (2017/04/20 10:50:24)? Right now I have this:
perl -ne '$l=$_ if /received/; END{print $l}; ($date) = $1 =~ m/^(\d+
+\/\d+\/\/d+) .*/g ; print $date, " \n" ' /var/log/rsync.log
Which should at least get me '2017/04/20' (just starting with the regex), but I get nothing back in $date, just the original line.
Is it possible to achieve in a oneliner, or do I need to write a proper script?
TIA.
EDIT: Thanks a lot for your solutions. The autosplit switch is really handy.
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