You assigned your line to $l (lowercased "L", a terrible variable name) but then tried to match against $1 (lowercased "!", a regex capture variable).

For the regex itself:

m/^(\d+\/\d+\/\/d+) .*/g

[download]

Using alternate delimiters reduces escaping, making the error obvious:

m!^(\d+/\d+//d+) .*!g

[download]

Also, the /g can be omitted.

In reply to Re: one liner question by Anonymous Monk
in thread one liner question by natxo

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