$_=~ s/"//g; but gives an error

A string substitute operation like this will not yield an error except in the case where the string that is being processed is undefined. In addition, $_=~ is not needed as the substitute operator will work on $_ by default. Likely cause of your problem is that you are not setting the default $_ variable. Show your code.

In reply to Re: perl script to remove part of double quote by Marshall
in thread perl script to remove part of double quote by sud100

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