Maybe this subroutine: 
use strict;
use warnings;

my @array = (-11,-13,4, 22, 17);
print find_max_odd(@array), "\n";
sub find_max_odd {
    my $max; 
    while ($max = shift) {
        last if $max % 2;
    }
    return "Not found" unless @array;
    while (my $current = shift) {
        next unless $current % 2;
        if ($current > $max) {
            $max = $current;
        }
    }
    return $max;
}

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Update: As pointed out by AnoMonk below, these while loops have a bug when one of the array item is 0.I suggest a better for loop in another post below.

In reply to Re: John Guttag's book - 2nd exercise. My attempt in Perl. by Laurent_R
in thread John Guttag's book - 2nd exercise. My attempt in Perl. by pritesh_ugrankar

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