How about this:
# Prepend $pwd as necessary
@p=();
foreach (split("/", $path)) {
pop @p, next if $_ eq '..';
next if $_ eq '.';
push @p, $_;
}
$path=join("/", @p);
It is clearer, in my opinion, but considerably slower:
Benchmark: timing 1000 iterations of Mikfire, Zamboni...
Mikfire: 1 wallclock secs ( 0.47 usr + 0.00 sys = 0.47 CPU)
Zamboni: 4 wallclock secs ( 3.23 usr + 0.00 sys = 3.23 CPU)
As given, your last solution produces double diagonals sometimes.
For the string '/home/zamboni/tmp/../lib/./tex/..' it produces
'/home/zamboni//lib//'. The solution is to match a second
optional diagonal after the (\.)?, like this:
while ( $path =~ s#(/[^/]+)?/\.(\.)?/?#defined($2) ? "/" : "$1/"#e ) {
+;}
--ZZamboni
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