Your main problem is that perl does not consider '09' to be a number. The function 'eval' will fail no matter what you do. Why not explicitly remove the leading zero?
use strict;
use warnings;
use Scalar::Util qw(looks_like_number isdual);
my $transf = '/3+6';
my $constant = '09';
my $var = \$constant;
#if (looks_like_number($$var)) {
if (!looks_like_number($$var)) { #correction per [haukex]
print "$$var is not a number\n";
}
else {
print "$$var looks like a number\n";
}
if (!isdual($$var)) {
print "$$var does not have a hidden numeric value\n";
}
$$var =~ s/^0*//; # make it into a valid number
my$expr = "$$var$transf";
my $ans = eval "$$var$transf";
print "$expr yields: ";
if (!$@) {
print $ans, "\n";
}
else {
print $@, "\n";
}
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