Hello Monks

I am getting the following warning after a code refactoring where the optional divisor value passed via a parameter hashtable can be undef (because non-existent in the hashtable), even when trying to use a condition. For example

if ($divide_by){
  $data_to_sum[0]->[$c] /= $divide_by;
}

[download]

and

$data_to_sum[0]->[$c] /= $divide_by if $divide_by;

result in the same warning. What is the correct way to do? Use a default value of 0 to make the test work?

The best programs are the ones written when the programmer is supposed to be working on something else. - Melinda Varian

In reply to Argument "" isn't numeric in division (/) by seki

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