shouldn't you really recalculate the sqrt every time you change x? Because the maximum remaining factor(s) will be less than or equal to the root of the new x, and depending on the size of the y, it could reduce the max significantly enough to overcome the cost of the root. As long as the sqrt is taken after the redo, not in the loop condition, the cost shouldn't be too bad for the payoff. (easily benchmarked)

In reply to Re^6: Avoid keeping larger lists in Memory by pryrt
in thread Avoid keeping larger lists in Memory by pr33

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