>I also do not understand why you instantiate $ii = -1; and on the next step 3 lines after you are adding 1 $ii = $ii + 1; which will result to 0. You can get this value from your for loop why you need to apply this calculation?
I removed this now with $ii and $i and use only $i.Regards, buchi
In reply to Re^2: question to a complex structure of hash/array
by buchi2
in thread question to a complex structure of hash/array
by buchi2
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