I don't understand, it IS an escaped quote and it works for me:
DB<175> $re = qr/ " (?: \\\\ | \\" | [^"] )* " /x; DB<176> p $a= q<x "..\\".." x> x "..\".." x DB<177> $a =~ /$re/; print $& "..\".."
maybe you should show us how you'd escape a double-quote.
Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
Je suis Charlie!
In reply to Re^5: Parser Performance Question (updated)
by LanX
in thread Parser Performance Question
by songmaster
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