no, your idea is not right... $_ is not really how args get passed, $_ is global and so in this codd its the same $_ in the sub and in the grep. "shift" shifts @_, and @_ is the args of the sub, in your code @_ is always just ($_) so thats why its the same here

In reply to Re: Grep: What is the reason following example code gives same result for both shift and $_? by Anonymous Monk
in thread [Answered]: Grep: What is the reason following example code gives same result for both shift and $_? by Perl300

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