First, Rats aren't FatRats and vice-versa.
They're both Rational, but that's still not very useful.
> my Rational $x = 1.111111111111111111111; 1.11111111111111111604544 > $x *= 0.1; Type check failed in assignment to $x; expected Rational but got Num ( +0.111111111111111e0)
The argument type-coercion is cute, but there doesn't seem to be any way to set the precision.
> sub foo(FatRat() $x) { return $x }; foo(pi).nude (355 113) > pi.FatRat(1e-8).nude (103993 33102)
And I don't know how to interpret this message...
> my FatRat() $x = 0.1; ===SORRY!=== Error while compiling: Coercion FatRat(Any) is insufficiently type-like to qualify a variable ------> my FatRat() $x⏏ = 0.1; expecting any of: constraint

In reply to Re^12: Small Perl 6 discoveries II, Rats by Anonymous Monk
in thread [Perl6] Small discoveries I, __DATA__ by holli

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