if($ID = $ID2 and $mac2 = ''){
  $$ref2{'Network ID 1'} = $mac;
}else{
  push @extras,\$ref;
}

[download]

Are you aware that the expressions  $ID = $ID2 and  $mac2 = '' are assignments and not comparisons? In any case, the  $mac2 = '' assignment will always be boolean false and the if-conditional will always be false. Probably what you meant was
    if ($ID == $ID2 and $mac2 eq '') { ... } else { ... }
because  $mac2 is certainly being compared to a string, and I suspect that  $ID == $ID2 is likewise a string comparison and therefore should be  $ID eq $ID2 instead.

Update: An example: 

c:\@Work\Perl\monks>perl -wMstrict -le
"my ($ID, $ID2, $mac2) = ('foo', 'foo', '');
 ;;
 if($ID eq $ID2 and $mac2 eq ''){
   print 'true block';
 }else{
   print 'false block';
 }
"
true block

c:\@Work\Perl\monks>perl -wMstrict -le
"my ($ID, $ID2, $mac2) = ('foo', 'foo', '');
 ;;
 if($ID = $ID2 and $mac2 = ''){
   print 'true block';
 }else{
   print 'false block';
 }
"
false block

[download]

Give a man a fish:  <%-{-{-{-<

In reply to Re: Searching between two hashes by AnomalousMonk
in thread Searching between two hashes by TStanley

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