My 2˘: perl -E 'say scalar map {1..$_} map {int (rand(50)+1)} (1..5);'

Update:

I guess i'll never learn it to read specs right.

Did you mean this?

  1. Pick up 5 random numbers from 1 to 50
  2. Add them
  3. Print the sum on one line
  4. Repeat this 5 times

If so, this should work: perl -E 'say scalar map {1..$_} map {int (rand(50)+1)} (1..5)  for 1..5'

Update 2:

If you want to use the numbers only once, this should work:

#!/usr/bin/env perl use strict; use warnings; use feature qw (say); my @n = ( 1 .. 50 ); # ad libitum: # open( my $urandom, "</dev/urandom" ) or die $!; # read( $urandom, $_, 4 ); # close $urandom; # srand( unpack( "L", $_ ) ); # for ( my $i = @n ; --$i ; ) { # my $j = int( rand( $i + 1 ) ); # next if $i == $j; # @n[ $i, $j ] = @n[ $j, $i ]; # } say scalar map { 1 .. $_ } map { splice( @n, int( rand(@n) ), 1 ) } ( 1 .. 5 ) for 1 .. 5; __END__

To be honest: i didn't test it very thoroughly ;-(

Best regards, Karl

«The Crux of the Biscuit is the Apostrophe»

perl -MCrypt::CBC -E 'say Crypt::CBC->new(-key=>'kgb',-cipher=>"Blowfish")->decrypt_hex($ENV{KARL});'Help


In reply to Re: Dice roll chances by karlgoethebier
in thread Dice roll chances by Anonymous Monk

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