It's a precedence problem.

B::Deparse with the -p option can show you how Perl understands expressions. Unfortunately, the expression contains only constants, so it's evaluated at compile time, so the result isn't helpful:

$ perl -MO=Deparse,-p 1.pl use strict; my($test); ($test = (undef)); print("test = $test\n"); 1.pl syntax OK

You need to introduce variables to postpone the evaluation to runtime to get a more enlightening answer:

#! /usr/bin/perl use warnings; use strict; my $test; my $undef; my $true = 1; my $zero = 0; $test = $true || ($undef && $undef != $zero) ? $undef : $zero; print "test = $test\n";

And, voilą:

use strict; my($test); my($undef); (my $true = 1); (my $zero = 0); ($test = (($true || ($undef && ($undef != $zero))) ? $undef : $zero)); print("test = $test\n"); 1.pl syntax OK

Nicely indented:

$test = ( ( $true || ( $undef && ( $undef != $zero ) ) ) ? $undef : $zero )

$true || ... returns 1, so the "then" part of the ternary is returned, i.e. $undef.

Maybe you wanted

$test = $true || ($undef && $undef != $zero ? $undef : $zero);

($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord }map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,

In reply to Re: Mixing OR with conditional operator by choroba
in thread Mixing OR with conditional operator by jockel

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