Look at it again: 
    open(WRITE,">$file") or die( "Cannot write to $file: $!" );

[download]
You are missing the point of his request. He wants to see what $file is, in addition to the $! variable. Why? Because the error "No such file or directory" begs the question "What file is the program trying to create, and in what directory?"

buckaduck

In reply to Re: Re: Re(3):: opening new file in different directory by buckaduck
in thread opening new file in different directory by George_Sherston

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