Ok, I was thinking about using a 86,400 element array. One for each second of the day (ranges crossing days would need some sort of sliding window and offset I guess). Anyway something to investigate perhaps.

#!/usr/bin/perl use warnings; use strict; my @range=(); while (<DATA>){ chomp; if (/^R:(.*)/){ my ($i,undef,$s,undef,$e) = split /[, ]/,$1; $s = sec($s); $e = sec($e); for ($s..$e){ $range[$_] = $i; } } else { my (undef,$t) = split /-/,$_; my $rangeid = $range[ sec($t) ]; if ( defined $rangeid) { print "Found range: $rangeid for $t\n"; } else { print "No range found for $t\n"; } } } sub sec { my ($h,$m,$s) = split /:/,shift; return $h*60*60 + $m*60 + $s } __DATA__ R:1,2018-03-06 14:20:00,2018-03-06 14:30:00 R:2,2018-03-06 13:00:00,2018-03-06 13:40:00 R:3,2018-03-06 13:45:00,2018-03-06 13:50:00 D:03/06/2018-14:29:41 D:03/06/2018-13:33:38 D:03/06/2018-13:54:47 D:03/06/2018-12:53:34 D:03/06/2018-13:29:19 D:03/06/2018-12:52:47 D:03/06/2018-14:21:51 D:03/06/2018-13:49:20 D:03/06/2018-13:36:18 D:03/06/2018-13:44:25
poj

In reply to Re^5: search through hash for date in a range by poj
in thread search through hash for date in a range by bfdi533

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