Hello Perl Monks,

I am trying to program series equation in Perl and solve for the 'x' at the end.

my equation is

$c = 1 or 0; - different value(0 or 1) for each for loop

$q is given value - different value each for loop though 

    for ($i=1; $i<1000; i++) {
 
      $sum_equ ={(1-$c[$i])(1-2*$q[$i])}/(-2*$q[$i]*$x +$x +$q[$i]) + 
+{$c[$i]*(2*$q[$i] -1)}/(2*$q[$i]*$x-$x+1)
    }

[download]

$c values determines which part of valued to be added.

I am hoping '$sum_equ' contains sum of all equations and set the final equations as zero, then solve for the $x value at the end.

for example...

I have 1000 iterations to to be begin with $sum_equ = 0;

      when i=0; $sum_equ = (1 - 2*10)/(-2*10*$x +$x +10);
      when i=1; $sum_equ = (1 - 2*10)/(-2*10*$x +$x +10) +(2*5 -1)/(2*
+5*$x-$x+1);
      .....

      when i=999; $sum_equ = (1 - 2*10)/(-2*10*$x +$x +10) +(2*5 -1)/(
+2*5*$x-$x+1)+ ....... + (2*22 -1)/(2*22*$x-$x+1);

[download]

then $sum_equ = 0

Solve for $x value

pseudo code would be... I am stuck at what functions to use or how to implement it... 


       for ($i=1;$i<1000;$i++) {

      if ($c==1) {

                        $sum_equ = $sum_equ + (1 - 2*$q[$i]/(-2*$q[$i]
+*$x +$x +$q[$i] );
                } elsif ($c ==0) {
                        $sum_equ = $sum_equ + (2*$q[$i] -1)/(2*$q[$i]*
+$x-$x+1);

                } # End of if

        } #end of for

[download]

I would greatly appreciate any comments or opinion.

Thank you so much.

2018-03-22 Athanasius Added code tags and removed paragraph tags from within code

In reply to Solve for 'x' in series by sbae

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