shift removes the first variable from the parameter-list, which is then assigned to the (arbitrarily-named) local variable self to provide access to the object. Many object programming languages use the technique of "a hidden first-parameter." Perl just does so explicitly.

In reply to Re: [SOLVED]: Trying to understand method calling in OOP by Anonymous Monk
in thread [SOLVED]: Trying to understand method calling in OOP by Perl300

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