EDIT:
After reading the responses to my post, I've come to two tentative conclusions: 1) I have only a loose grasp of how references work in Perl. It's obvious I have a lot to learn on the subject. 2) In this case, I'm mistaking output for content (Data::Dumper does not represent the reference structure's content in the way I imagined). 3) This is frustrating but fun as hell.
Here's my edited code that gives me what I want (thank you all for helping me with this):
sub inc{
my $ref=shift;
my $span=shift;
$span?($span--):($span=1);
my @b=map{ clone([@$ref[$_-$span..$_]]) }($span..$#$ref);
\@b
}
sub clone{#clone references
my $ref=shift;
my@array=map{ ref($_)?clone($_):$_ }@$ref;
\@array
}
my@b=(1..5);
my $c = inc(inc(\@b));
print Dumper $c;
Which produces:
$VAR1 = [
[
[
1,
2
],
[
2,
3
]
],
[
[
2,
3
],
[
3,
4
]
],
[
[
3,
4
],
[
4,
5
]
]
];
Woohoo!
ORIGINAL POST:
I have come across a strange thing. If I run the following code with an array of scalars, then I get what I expect. E.g.,
@a = (1,2,3,4,5,6);
increment(\@a);
#produces tuples of:
[1,2],[2,3],[3,4],[4,5],[5,6] #yay!!
But, I want to run increment() with arrays of arrays. But, the result is all sorts of funky.
Here's Data::Dumper output:
$VAR1 = [
[
[
1,
2
],
[
2,
3
]
],
[
$VAR1->[0][1],
[
3,
4
]
],
[
$VAR1->[1][1],
[
4,
6
]
]
];
I'm using the following test code:
my @a = (1,2,3,4,6);
print Dumper increment(increment(\@a));
sub increment{
my $d=shift;
my @b;
for my $i (1..$#$d){
my @a = @$d[$i-1..$i];
push @b,\@a;
}
\@b
}
The output is half-right --the second part of each tuple is itself a tuple (and is what's expected). But, what's with the first part of each tupple? The
"$VAR->[n][1]"
I am flummoxed.
Thanks much for whatever advice you might have.
$state{tired}?sleep(40):eat($food);
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