This code does not work...

alarm 2;
$SIG{ALRM} = \&Finish;
my $a=<>;

sub Finish { print "Timeout reached"; }

[download]

This code does not work either...

alarm 2;
$SIG{ALRM} = \&Finish;
while (1==1){};

sub Finish { print "Timeout reached"; }

[download]

So i guess many calls are not interrumptibles... am i right>?

In reply to Re^4: Print inside SIGNALS by pedrete
in thread Print inside SIGNALS by pedrete

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