AFAIK, Perl 5.x has always supported this

I'm having some trouble running a bisect at the moment, but as a tentative result, it appears that Perl versions roughly before 5.004 didn't like the test program -e '$a="f.o.o.bar"; $b=()=$a=~/\./g; $b==3 or die $b' because Can't modify stub in list assignment at -e line 1, near "/\./g;". AFAICT it was not possible to assign to an empty list back then (a workaround seems to be $b = @{[]} = $a =~ /\./g;, which works on 5.000).

In reply to Re^2: Syntax Perl Version support $c = () = $a =~ /\./g by haukex
in thread Syntax Perl Version support $c = () = $a =~ /\./g by h2

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