( echo '<foo>3</foo>'; echo '<foo>14</foo>'; echo '<foo>159</foo>') | +perl -e ' my $x = 0; while (my $l = <>) { $x++; $l =~ s/\d+/$x/; print $l; }' <foo>1</foo> <foo>2</foo> <foo>3</foo>
One world, one people
In reply to Re: sequential substitutions
by anonymized user 468275
in thread sequential substitutions
by Anonymous Monk
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