At first glance, $foo will end up holding a map and an inverted map drawn from @a. Looks like a long-winded way of saying   %foo = (@a, reverse @a); In which case $foo{"c"} would be 3.

On second glance, first glance was wrong, wrong, wrong. It's   %foo{@a} = reverse @a;

Partial credit?

In reply to Re: Tuesday Evening Code Quiz by dws
in thread Tuesday Evening Code Quiz by davorg

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