\0, \1, \2, etc. are NOT hexadecimal character codes, but OCTAL. For what you intended, you'd need \10 or \x8, or what nysus wrote. "Accidently", 0 - 7 octal and hexadecimal are the same.

Update: And, this part \n\0x0B\r\0x0D is wrong - \r is not 0xC but 0xD, so you're skipping chr(12) and have a double chr(13).

In reply to Re: Question about tr by soonix
in thread Question about tr by harangzsolt33

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