One more way. Copy your hash keys to arrays, and do a binary
search. The setup is O(n*log(n)), but the advantage is that
the lookups are O(log(n)) (Not quite the O(1) as you wanted,
but pretty good). (all untested, but pretty much lifted from
Array::IntSpan,
which I've seen alot of lately :)
my @array = sort keys %hash;
# Keep another array for regexps
my @regexes = map qr/^$_/, @array;
for my $ph_num (@phone_numbers) {
my $num = search($ph_num) || 'not';
print "$ph_num $num found\n"
}
sub search {
my $num = shift;
my ($start, $end) = (0, $#array);
while ($start < $end) {
my $mid = ($start+$end)/2;
if ($array[$mid] le $num) {
return $hash{$array[$mid]} if $num =~ $regexes[$mid];
$start = $mid+1;
} else {
$end = $mid-1;
}
}
$num =~ $regexes[$start] && $hash{$array[$start]};
}
Update: Added slight optimization. We are
still occasionally repeating the last regex, that's ok though. I don't think there's an optimal way to eliminate it (or I just don't feel liking looking for it at the moment :).
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