This little demo in the debugger (without strict) should make it clearer

DB<5> print "x".NAME # bareword treated as string xNAME DB<6> sub NAME {42} # sub declaration DB<7> print "x".NAME # bareword now known to be s +ub x42 DB<8> print "x".NAME2() # explicit sub call Undefined subroutine &main::NAME2 called at (eval 17)[C:/Perl_524/lib/ +perl5db.pl:737] line 2. DB<9> print "x".&NAME2 # explicit sub call Undefined subroutine &main::NAME2 called at (eval 18)[C:/Perl_524/lib/ +perl5db.pl:737] line 2. DB<10>

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery FootballPerl is like chess, only without the dice


In reply to Re^2: New Discovery!!! (sub call without parentheses) by LanX
in thread New Discovery!!! (sub call without parentheses) by harangzsolt33

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