I was going to just edit my post after I got my perlbrew available issue sorted (which I did), but this warrants a new post.

In 5.10, it produces the result aa that is expected by OP:

spek@scelia ~/scratch $ perlbrew exec perl -le '@_ = qw( a b c ); @A = + ( shift @_ )[ 0, 0 ]; print @A' perl-5.27.10 ========== aa perl-5.26.1 ========== aa perl-5.20.0 ========== aa perl-5.18.4 ========== a perl-5.10.1 ========== aa

Going full out, and am installing as many versions as I can to see where it "broke", where it "fixed" and where it "broke" again. Help desired.

Update: To further, on Unix, it "works" up to 5.12.5, from my testing so far, then goes awry:

spek@scelia ~/scratch $ perlbrew exec perl -le '@_ = qw( a b c ); @A = + ( shift @_ )[ 0, 0 ]; print @A' perl-5.27.10 ========== aa perl-5.26.1 ========== aa perl-5.20.0 ========== aa perl-5.18.4 ========== a perl-5.16.0 ========== a perl-5.14.4 ========== a perl-5.12.5 ========== aa perl-5.10.1 ========== aa

In reply to Re^4: Case where '( shift @_ )[ 0, 0 ]' returns only one value? by stevieb
in thread Case where '( shift @_ )[ 0, 0 ]' returns only one value? by rsFalse

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