To reduce surprise, the function should return true if the number is valid, and false otherwise, which is the other way round.

There's no need to backslash a space in regular expressions. Moreover, there's no need for a substitution in this case, transliteration does the same job (and is simpler and faster).

There's a pattern in the computation of the sum which could be expressed by a for loop.

See my version below:

sub check_abn { my ($number) = @_; $number =~ tr/ //d; return if 11 != length $number; my $sum = 0; $sum += (2 * $_ - 1) * substr $number, $_, 1 for 1 .. 10; $sum += 10 * (substr($number, 0, 1) - 1); return $sum % 89 == 0 }

map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

In reply to Re: ABN checker by choroba
in thread ABN checker by bgroper

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