I guess something like this? I would probably return just a 0 or 1 for a true/false value. Here "True" and "False" just happened so the printout looked nice.
#!/usr/bin/perl use strict; use warnings; my $x = isABN("51 824 753 556"); print "$x\n"; $x = isABN("51 824 755 556"); print "$x\n"; sub isABN # returns True if ABN, False if not an ABN { my $abn = shift; $abn =~ tr/ //d; #delete spaces return "False" unless (length $abn == 11); my @digits = split '',$abn; $digits[0] -= 1; my @weights = (10,1,3,5,7,9,11,13,15,17,19); my $sum =0; for my $i (0..10) { $sum = $sum + ($digits[$i] * $weights[$i]); } print "sum = $sum\n"; #for debugging... return ($sum % 89 == 0? "True": "False"); } __END__ sum = 534 True sum = 560 False

In reply to Re: ABN checker by Marshall
in thread ABN checker by bgroper

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