Hey folks,

I'm having a problem. I'm porting some perl to C to speed it up, and I can't get the two languages to agree on what's going on. I'm using ActiveState's perl 5.24.1 for Windows. Consider the following code:


$test = "\n\n\n\n\n";

for ($x = 0; $x < length($test); $x++) {
    print ord(substr($test, $x, 1));
    <STDIN>;
}

The code prints a string of 10s, indicating that the 13/10 combination in Windows has been translated to a bare 10. I can understand that, for compatibility reasons. But it seems to mean there is no way in Windows of telling a 13/10 combo from a bare 10. This makes a difference in my code, in that I can't get C and perl to hash the same string the same way. Am I missing something? Is there no way at all to tell a 13/10 from a 10 in Windows perl?

I believe the upshot of this, where my code is concerned, is that perl is doing it "wrong" compared to C and I'll never get the two to agree. I hope I'm wrong about that. I note with interest and mild annoyance that strlen("\n") == 1 even in C for windows. But C allows me to get at the underlying character buffer and perl does not.

Thanks,

Lars

In reply to Perl to C problem by lbrandewie

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