> fair enough, both work.

Still different, your result is a string.

Perl works hard to treat all scalar sub-types equally by operators, but I seem to remember edge cases where the internal type mattered and resulted in errors.

No need to stringify a number.

And a reader - at least me - would be confused.

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery FootballPerl is like chess, only without the dice

In reply to Re^4: u+ fails to force scalar context to empty list assignment: +( () = ... ) by LanX
in thread u+ fails to force scalar context to empty list assignment: +( () = ... ) by rsFalse

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