Which statement was your "no" responding to? The original statement I believe is: "With for(@tied_array) we also doesn't need to calculate the length of the list in advance" which you said "That's not true." which I then demonstrated with Range::ArrayIter, which then you replied to with "no" followed by cases where tied-array-based iterator would fail. Sure, the tied-based iterator does not work in all cases, but we are talking specifically about a single "for(@tied_array)".

What I want to know is why you said (in essence) that "With for(@tied_array) we still need to calculate the length of the list in advance".

In reply to Re^12: Getting for() to accept a tied array in one statement by perlancar
in thread Getting for() to accept a tied array in one statement by perlancar

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