This reduces the degrees of freedom of the ^ $ . operators
Maybe that hints at the following inconsistency I see with the "the end of the line (or before newline at the end)" rule?

Example

print('String: a\nb\nc\n' . "\n");
$text_1 = "a\nb\nc\n";
$text_1 =~ s@(\n)$@@s;
print("----------\n>" . $1 . "<\n");
print("----------\n>" . $text_1 . "<\n");

[download]
Gives: 
String: a\nb\nc\n
----------
>
<
----------
>a
b
c<

[download]
In this case, the $ behaved like \z. Or another way to say it, in this case explicit \n matches where dot with s mod doesn't.

In reply to Re^2: How to match last character of string, even if it happens to be a newline? by Allasso
in thread How to match last character of string, even if it happens to be a newline? by Allasso

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