I have this really annoying problem that I can't seem to figure out... I need to create a hash that contains two sets of arrays embedded. Editting the array in the hash would look like this:

$db{'key1'}{'key2'}[0][0] = "one_value";
$db{'key1'}{'key2'}[0][1] = "two_value";
$db{'key1'}{'key2'}[1][0] = "three_value";
$db{'key1'}{'key2'}[1][1] = "four_value";
$db{'key1'}{'key2'}[2][0] = "three_value";
$db{'key1'}{'key2'}[2][1] = "four_value";

[download]

Or maybe like this, I'm not sure:

@{$db{'key1'}{'key2'}[0][0]} = "one_value";
@{$db{'key1'}{'key2'}[0][1]} = "two_value";
@{$db{'key1'}{'key2'}[1][0]} = "three_value";
@{$db{'key1'}{'key2'}[1][1]} = "four_value";
@{$db{'key1'}{'key2'}[2][0]} = "three_value";
@{$db{'key1'}{'key2'}[2][1]} = "four_value";

[download]

Now, under the key2 key, I don't know how many values are in that array. (The first set of array numbers, namely 0, 1, and 2). The second set of array numbers (The constant 0 and 1) are always there and only have the indexes 0 and 1.

Could someone please give me an idea what this hash structure would look like, and how I would go about getting the last index number of the first set of array numbers. (Something like $#{$db{'key1'}{'key2'}} maybe?)

And also, how would I go about deleting the array? I don't want to do delete $db{'key1'}{'key2'}, but something more along the lines of  delete $db{'key1'}{'key2'}[3].

Thanks ahead of time!

In reply to Array in a Hash by mt2k

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