You can use the flip-flop operator ".." for that. Read perlop to find out how it works. Note that .. isn't a list constructing operator in scalar context.

while (<DATA>){ next if 1 .. /^Buffers/; print; } # I copied the line with the numbers several times, # to convince myself that the script wouldn't stop # after printing just the first. __DATA__ DDR -- Running -- # Event Snoopy Snoopy Replay Replay Current Current Buffers ID Position ID Position ID Position 1024 1667721 2975e7c 1667717 6d44e10 1667721 2982000 1024 1667721 2975e7c 1667717 6d44e10 1667721 2982000 1024 1667721 2975e7c 1667717 6d44e10 1667721 2982000

2;0 juerd@ouranos:~$ perl -e'undef christmas' Segmentation fault 2;139 juerd@ouranos:~$


In reply to Re: Getting the next line after a match by Juerd
in thread Getting the next line after a match by dthacker

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