chop() wants an lvalue (like a variable), because it modifies its argument. The result of reverse is not an lvalue, so you lose.

-- Randal L. Schwartz, Perl hacker

In reply to Re: First char out of a string & surprises with errors on chop reverse $string (that doesn't work!) by merlyn
in thread First char out of a string & surprises with errors on chop reverse $string (that doesn't work!) by eduardo

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