merlyn is quite right...had I not been in the shower, I could have saved you the post :)

For those of you who may not know what merlyn means by a lvalue...look at it this way. chop removes the last character from the scalar you pass it modifying the scalar. Since you passed it the return value from reverse, it didn't have a 'real' scalar to chop, thus the error.

/\/\averick
perl -l -e "eval pack('h*','072796e6470272f2c5f2c5166756279636b672');"

In reply to Re: First char out of a string & surprises with errors on chop reverse $string (that doesn't work!) by maverick
in thread First char out of a string & surprises with errors on chop reverse $string (that doesn't work!) by eduardo

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