It works, but I guess you've also got to consider the possibility that the URL will contain query parameters, like this: http://www.site.com/dir/file.html?param1=val1&param2=val2

So a second substitution (I'm sure you can do it with a lookahead assertion or similar, but that seems a bit overkill) is probably in order:

$file =~ s/\?.*//;

Cheers,
-- moodster

In reply to Re: Re: A better way? Extracting filename from url by moodster
in thread A better way? Extracting filename from url by Gerard

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