Hi Perlmonks.. I want to ask concerning this code below: 
print OUT join ";", map {${$_}[1],${$_}[2]} grep { ${$_}[0] eq "EMBL" 
+} $entry->DRs->elements(); 

INPUT :
DR EMBL;ABC;DEF;-.
DR EMBL;GHI;JKL;-
DR PIR;MNO;PQR;-

OUTPUT :
EMBL ABC;DEF;GHI;JKL;

[download]
Basically the $entry->DRs->elements() will return a reference to a list called DR.. in this case we reffered to the list whose first element=EMBL. Is there any way to make my output looks like the input... by modifying the map and grep function above? I tried to separate the map into two parts : 
print OUT join ";", map {${$_}[1]}grep { ${$_}[0] eq "EMBL" } $entry->
+DRs->elements(),map {${$_}[2]} grep { ${$_}[0] eq "EMBL" } $entry->DR
+s->elements(),"\n";

[download]
But the print out is still the same... Thanks in advanced...

In reply to put only 2 elements in a line by agustina_s

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