To pass a file from the command line use @ARGV instead of <STDIN>. So your code:
my $processfilename=''; 
print "\nEnter filename to process (type exit to quit): "; 
chomp ($processfilename = <STDIN>);

[download]
Could be:
my $processfilename=$ARGV[0];

[download]


Sparky
FMTEYEWTK

In reply to Re: New Perl User Question by sparkyichi
in thread New Perl User Question by Rpick

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