i am looking at a piece of code that can be simplified to the following...

#!/usr/bin/perl -w
use strict;
my @list = qw(Charles Cody Gina);
&action;

sub action {
  for my $i(@list) {
    &decide($i);
  }
}

sub decide {
  my $i = shift;
  next if (/^C/);
  print "$i\n";
}

[download]

the next if statement causes the script to spit out an error that it "Exiting subroutine via next at Script line 14". i can see where this error would come up, since, according to the subroutine, there is no list, just a single value for $i that is being passed to it.
is there a method of maintaining my structure and would allow me to exit the subroutine for the specific value within the list? sorry that this example is simplified rather than providing the entire code snippet. rather that seeking a rewrite to solve my code issue, i am more interested in finding out if it is possible to drop out of a sub routine's action without exiting the script entirely.

thanks! -c

In reply to next within one subroutine that looks to another subroutine by c

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