Yeah, I know this is a very simple piece of code... but I don't have anything else in my reportoire worth posting right now. ;-)

Feed it an integer, and it will print all possible permutations ($a/$b/$c) of right triangles. 
#!/usr/bin/perl

use strict;
my ($a, $b, $c);
my $max = shift || die "Usage: pythag.pl <max len>\n";

for ($a=1; $a<$max; $a++) {
        for ($b=1; $b<$max; $b++) {
                for ($c=1; $c<$max; $c++) {
                        if ((($a**2) + ($b**2)) == ($c**2)) {
                                print "$a $b $c is a winner\n";
                        }
                }
        }
}

[download]
-fuzzyping

In reply to Pythagorean's theorem by fuzzyping

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