The
POSIX function
strtol provides a straightforward method of converting from a Base36 number. Unfortunately, there isn't an equivalent
ltostr.
Here is an un-golfed solution. It edits the number in-place.
There is a optimisation at the beginning that uses a simple string increment for numbers that don't end in 9 or Z. This gives a speed-up for 17/18 of the Base36 range.
#!/usr/bin/perl -w
use strict;
use POSIX 'strtol';
my @chars = (0..9, 'A'..'Z');
sub inc36 {
my $num = $_[0];
if ($num !~ /[9Z]$/) {
$num =~ tr/0-9/a-j/;
++$num;
$num =~ tr/a-j/0-9/;
return $_[0] = $num;
}
my $int = 1 + strtol($_[0], 36);
my $base36 = '';
while ($int) {
my $frac = $int % 36;
$int = int ($int / 36);
$base36 = $chars[$frac] . $base36;
}
$_[0] = $base36;
}
--
John.
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