#!/usr/bin/perl

use strict;
my $max = shift or die "Usage: $0 <max len>\n";
for my $t ( 2..sqrt$max ){
    for my $s ( 1..$t-1 ){
        my $c=$t*$t+$s*$s;
        next unless $c <= $max;
        my $a = $t*$t-$s*$s;
        my $b = 2*$s*$t;
        print "$a $b $c is a winner\n";
    }
}

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In reply to Re: Re: Re: Pythagorean theorem by I0
in thread Pythagorean's theorem by fuzzyping

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