How can I use something like $$a without angering strict refs ?

Also, why does the code below print "1" instead of "2"? I guess I have used $$a before and predicted what the outcome would be, but now its time to find out its really doing. :> 
my $a='b';
my $b='1';

$$a='2';

print $b;

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In reply to can't use string as a SCALAR ref while strict refs by justinNEE

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