Just a reminder:

Syntax of for:

for (init something;test;do something) {
    stuff
}

In the first for, you don't init anything, have a long test, and do nothing, so you could also write the first line as a while-loop:

while ($_?$,:(${_} = q...q,.,.qq,$=,^q.$..$= => $_=q,.,.chr ord)) {

Here you first check if $_ is defined. If it is, you return $, which defaults to undef, thus ending the loop. If $_ is not defined (the default), we enter this statement:

${_} = q...q,.,.qq,$=,^q.$..$= => $_=q,.,.chr ord

Now, lets de-obfuscate:

${_} is the same as $_, the curly braces beeing used like in @{$arrayref}

q.. . q,., . qq,S=, ^ q.$. . $= => $_=q,., . chr ord

looks like

 '' . '.'  .   "$=" ^  '$' . $= ,  $_= '.' . chr ord

when using normal quotes.

This is a list consisting of two items:

'' . '.'  .   "$=" ^  '$' . $=

and

$_= '.' . chr ord

Lets look at the first part:

'' . '.' . "$=" ^ '$' . $=

This uses ^ as XOR, which somehow means (i'm not tha good at bitwise stuff)

that each bit on the left of ^ gets XOR'ed with each bit on the right, so:

'.$=' ^ '$60'

(where is the 60 coming from? $= or $FORMAT_LINES_PER_PAGE defaults to 60) which yields the linebrake used in the cascade.

Now, the second part:

$_= '.' . chr ord

This is very intuitive way to write

$_= '.'.$_

ord converts the contents of $_ into the numeric ascii value. Those values then get passed to chr, wich converts numeric asscii values to the corresponding character.

Adding the two parts together, we now have:

($_="\n",$_='.'.$_;)

Which can be further simplified to:

($_=".\n")

So the whole first line looks now like

for(;$_ ? undef : ($_=",\n") {

for(s .. Just another perl hacker.) {

Here you use a . as a regex-separator, so this looks like

for(s//Just another perl hacker/) {

which substitutes the first empty string in $_ with 'Just another perl hacker' and therefor is the same as

s//Just another perl hacker/;

for(;s;.;;;print){ }

remebering the for-syntax, you here again intialise nothing.
The continuination-test looks de-obfuscated like s/.//
which a) removes the first char of $_ (thus causing the cascading effect) and b) returns undef if $_ is empty, stopping the for-loop and instead of incrementing a counter (which is usually done here), you just print $_.
The loop itself does nothing;

So:

while (s/.//) {
      print $_;
}

We end up with:

while($_ ? undef : ($_=".\n")) {
    s//Just another perl hacker/;
    while (s/.//) {
        print;
    }
}

Now lets de-obfuscate the algorithm

The stuff inside the main for-loop is quite easey:

Put "Just another perl hacker" into $_, chop of the first char and print it.

The interesting stuff happens in the definintion of the first while loop

If $_ is defined, return undef. As $_ is not defined by default, in the first run, do the other part if the ? : statement, which sets $_ to "\n."

Now we enter the code in the while-loop, that adds "Just another perl hacker" in front of $_ and than prints the cascade.

That's it (I think ...)

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