the formula:
4d6, discard 1s and add the three highest rolls. Do this six times.

yup pretty standard D&D ability rolls :)

So here's the questions:

using
#! /usr/local/bin/perl
use warnings ;
use strict ;

#Die Roller: uses 4d6 discarding the lowest number
#rerolling any roll of 1

my $roll = 6 ;

until ($roll == 0) {
    chomp $roll ;
    $roll -- ;
    my $d61 = int(rand(6) + 1) ;
    my $d62 = int(rand(6) + 1) ;
    my $d63 = int(rand(6) + 1) ;
    my $d64 = int(rand(6) + 1) ;
    print "$d61, $d62, $d63, $d64\n\n" ;
}

[download]
I get output like:

5, 2, 5, 4
4, 3, 6, 4
3, 6, 4, 5
5, 1, 2, 3
6, 5, 5, 2
2, 6, 5, 1

OK so I'll use an if/else statment to reroll the 1s (does that sound reasonabe?) but how do I figure out and discard the lowest number?
--
ellem@optonline.net
There's more than one way to do it, just don't use my way.

In reply to Trick die rolling by ellem

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