in any 1 roll, it rerolls the lowest number. It will also add the three highest sets of rolls and print it out. I know my version isn't as well done as others, but i didn't sit down to really work with it.. just fixed your code here and there to try and keep as much of it intact :). 
#!/usr/bin/perl
use warnings;
use strict;

#Die Roller: uses 4d6 discarding the lowest number
#rerolling any roll of 1

my $roll = 6;
my @sums;

until ($roll == 0) {
    my @d6;
    chomp $roll;
    $roll--;
    $d6[0] = int(rand(6) + 1);
    $d6[1] = int(rand(6) + 1);
    $d6[2] = int(rand(6) + 1);
    $d6[3] = int(rand(6) + 1);
    @d6 = sort @d6;
    $d6[0] = int(rand(6) + 1); #reroll lowest number
    my $sum = $d6[0] + $d6[1] + $d6[2] + $d6[3];
    push(@sums, $sum);

    print "$d6[0], $d6[1], $d6[2], $d6[3] : $sum\n\n";
}

@sums = sort @sums;
my $three_highest = $sums[3] + $sums[4] + $sums[5]; #add three highest
+ numbers in array
print "total of three highest roles : $three_highest";

[download]
EDIT... posted too quick and didn't even read your post in whole (missed the reroll of ONLY 1's)... i guess you didn't want one that looked like your version either :P, nonetheless, i'll keep the code here for you :).

In reply to Re: Trick die rolling by Parham
in thread Trick die rolling by ellem

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